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ddd [48]
3 years ago
10

Help ASAP no links or I’m reporting

Chemistry
1 answer:
seraphim [82]3 years ago
8 0

Answer:

three

because the circles represent a peak in each.

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PLEASE HELP ME I WILL BRAINLIST YOU AND GIVE YOU POINTS ​
MissTica

Answer:

Carbon 12 and carbon 13

Carbon isotope 12 exist as 98.9%

Explanation:

8 0
3 years ago
Read 2 more answers
A certain reaction has an activation energy of 67.0 kJ/mol and a frequency factor of A1 = 4.20×1012. What is the rate constant,
MrRa [10]

Answer:

  • K = 7.00

Explanation:

<u>1) Arrhenius equation</u>

Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.

This is the equation:

       K=Ae^{-Ea/RT}

Where:

  • K is the equilibrium constant,
  • A is the frequency factor,
  • Ea is the activation energy (in J/mol),
  • T is the temperature in kelvins (K), and
  • R is the universal constant.

<u></u>

<u>2) Substitute, using the right units, and compute:</u>

  • A = 4.20 × 10¹² (dimensionless)
  • Ea = 67.0 kJ/mol = 67,000 J/mol
  • T = 24.0°C = 24.0 + 273.15 K = 297.15 K
  • R = 8.314 J/K mol

K=Ae^{-Ea/RT}=(4.20)(10)^{12}e^{-67,000J/mol/(8.314J/molK.297.15K)}

  • K = 7.00
5 0
3 years ago
Select the formula for the following acid: Carbonic Acid
Nina [5.8K]

Answer: 106

Explanation:

Follow PEMDAS. 7x12 = 84

84 + 13 = 97

97 + 9 = 106

4 0
3 years ago
using information in titles of appendices b and c, calculate the minimum grams of propane, C3H8 (g), that must be combusted to p
Lubov Fominskaja [6]

<u>Given:</u>

Mass of ice = mass of water = 5.50 kg = 5500 g

Temperature of ice = -20 C

Temperature of water = 75 C

<u>To determine:</u>

Mass of propane required

<u>Explanation:</u>

Heat required to change from ice to water under the specified conditions is:-

q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)

  = m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)

  = 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ

The enthalpy change for the combustion of propane is -2220 kJ/mol

Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane

Molar mass of propane = 44 g/mol

Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g

Ans: 75.15 grams of propane must be combusted.



4 0
4 years ago
Please help I need the answer by today and it is very important! Which of the following statements best describes why the mass o
Juliette [100K]

D, because matter does not change in space but unlike gravity, which changes, matter, is the mass of it, which will stay the same unless there is a chemical change or, physical change, but not in this case, so the answer you are looking for is D. hope this enlarged your understanding and knowledge.

6 0
3 years ago
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