Answer:

Explanation:
The balanced equation is
2COF₂ ⇌ CO₂+CF₄; Kc = 9.00
1. Set up an ICE table

2. Solve for x
![K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cdfrac%7B%5B%5Crm%20CO%5D%5B%20%5Crm%20CF_%7B4%7D%5D%7D%7B%5B%5Crm%20COF_%7B2%7D%5D%5E%7B2%7D%7D%20%3D%209.00%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Brcl%7D%5Cdfrac%7Bx%5E%7B2%7D%7D%7B%282.00%20-%20x%29%5E%7B2%7D%7D%20%26%20%3D%20%26%209.00%5C%5C%5Cdfrac%7Bx%7D%7B2.00%20-%20x%7D%20%26%20%3D%20%26%203.00%5C%5Cx%20%26%20%3D%20%263.00%282.00%20-%20x%29%5C%5Cx%20%26%20%3D%20%26%206.00%20-%203.00x%5C%5C4.00x%20%26%20%3D%20%26%206.00%5C%5Cx%20%26%20%3D%20%26%20%5Cmathbf%7B1.50%7D%5C%5C%5Cend%7Barray%7D)
3. Calculate the equilibrium concentration of COF₂
c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

Check:

OK.
Answer:
The temperature is the same overtime.
Explanation:
Since the line on the graph is straight the temperature will be constant.
Answer:
0.465
Explanation:
To find the volume of a substance, divide the mass by the density.
M/D = V
10.0 / 21.5 = 0.4651163
Then round to 3 significant figures: and the density is 0.465
Answer:
property can also refer to a belonging or someone's property/items