Answer:
11
Step-by-step explanation:
You replace all the x with 12 when its f(12). if its f(3) you would replace all the x with 3.
So,
f(12)=2/3(12)+3
f(12)=8+3
f(12)=11
15 mi/h= 15mi/60 min= 1/4 (mi/min)
x is original speed (mi/min)
t is original time
x*t =260
(x+1/4)=5x/4 is new speed
t-20 - new time
(x+1/4)(t-20)=260
xt = (x+1/4)(t-20)
xt=xt + t/4 - 20x - 5
t/4=20x+5
t=80x +20
We can substitute t=80x +20 into equation x*t =260
x*(80x+20)=260
80x²+20x-260=0
4x²+x-13=0
D=b² - 4ac = 1+4*4*13= 209
x=(-1+/-√209)/2*4
x=1.68 mi/min
1.68mi/min * 60 min/1h≈100 mi/h
Check
260/100=2.6h time with old speed
260/(115)=2.26 h time with new speed
2.6-2.26 = 0.34 h difference between old and new time
0.34h*60min/1h≈20 min difference between old and new time in minutes
Answer:
long time huh You a fan of bts
It would come out to 3x = 3x so it would be infinitely many solutions
The area of deltoid is defined by formula:
Where e and f are diagonals.
If you were to double the size of either one. Let's say f. You would result with:
Which means if either of diagonals double in length the area of deltoid will be twice as big as it was before.
Hope this helps.
r3t40
