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2 years ago

12

Please help!!! I just need a simple explanation I will mark brainliest!

1 answer:

aniked [119]2 years ago

6 0

Answer:

I have made it in above figure so each angle will 150 degree

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Attachment is shown in the bottom

Leokris [45]

Answer: She is correct because each ratio is equivalent to 5:1, except for the last one, which is 1:5

5/1 = 5:1

10/2 = 5:1

25/5 = 5:1

10/50 = 1:5

5 0

3 years ago

Which of the following is equivalent to? 19

11Alexandr11 [23.1K]

Answer:

we dont see the numbers

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A machine wheel spins at a rate of 500 revolutions per minute. If the wheel has a diameter of 80 centimeters, what is the angula

solmaris [256]

Answer: 3,140 radians per minute.

Step-by-step explanation:

We know that the wheel does 500 revolutions per minute.

This is called the frequency of the wheel, and this is written as:

f = 500 rev/min = 500 RPM

The angular speed (or Angular velocity) is written as

ω = 2*pi*f

And this quantity is in radians/unit of time.

where pi = 3.14

then:

ω = 2*3.14*500 (rev/min)*(rad/rev) = 3,140 rad/min

This means that the angular velocity (or angular speed) is 3,140 radians per minute.

8 0

2 years ago

Read 2 more answers

Twelve more than the product of a number and 5 is 52

antoniya [11.8K]

Let the unknown number be y.
We can list the equation out by the clues given.
5y + 12 = 52
Then solve this as simple algebra!
Shift +12 to the other side and be - 12
5y = 52-12
5y = 40
Shift x5 to the other side and be ÷5
y = 40 / 5
y = 8
Therfore the unknown number is 8.

7 0

3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

3 years ago