Answer:
32 turns
Explanation:
From the expression for the induced emf,
E = (N)(B)(A) w
E = emf = 24 V
N = number of turns = ?
B = magnetic field strength = 0.10 T
A = Cross sectional Area of the loop = 100 cm² = 0.01 m²
w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s
24 = N (0.1)(0.01)(754.3)
N = (24/0.7543)
N = 31.8 ≈ 32 turns.
Hope this Helps!!!
Answer: 0.43 V
Explanation:
L = [μ(0) * N² * A] / l
Where
L = Inductance of the solenoid
N = the number of turns in the solenoid
A = cross sectional area of the solenoid
l = length of the solenoid
7.3*10^-3 = [4π*10^-7 * 450² * A] / 0.24
1.752*10^-3 = 4π*10^-7 * 202500 * A
1.752*10^-3 = 0.255 * A
A = 1.752*10^-3 / 0.255
A = 0.00687 m²
A = 6.87*10^-3 m²
emf = -N(ΔΦ/Δt).........1
L = N(ΔΦ/ΔI) so that,
N*ΔΦ = ΔI*L
Substituting this in eqn 1, we have
emf = - ΔI*L / Δt
emf = - [(0 - 3.2) * 7.3*10^-3] / 55*10^-3
emf = 0.0234 / 0.055
emf = 0.43 V
At the most distant point, the size of the speed is zero (0 m/s). This is a direct result of preservation of vitality. PE = KE. The most distant far from the harmony position is the maximum PE. Hence it can have no KE. No KE implies no speed since KE = .5mv2