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34kurt
4 years ago
14

One normal afternoon in undisclosed City X, the chocolate factory workers overload the Easter egg machine. A group of angsty tee

ns cutting school at the edge of City X see a large explosion from across town as the factory explodes, covering the rooftops in unrefined sugars. Five seconds later, they hear the boom. Approximately how far are they from the factory? show work
A. 68.6 m
B. 145 m
C. 1,715 m
D. 60,000 m
Physics
1 answer:
musickatia [10]4 years ago
8 0

Answer:

The correct option is;

C. 1,715 m

Explanation:

We are given the information from the group of teen at the City edge

Time of arrival of explosion sound = 5 s after sighting

Time of sighting explosion = 5 s before hearing the boom

Speed of sound in air ≈ 343 m/s

Speed of light = 299,792 km/s

Therefore, distance covered by sound in 5 seconds is given by the following equation;

Speed = \frac{Distance}{Time}

\therefore 343 \ m/s= \frac{Distance}{5 \, s}

Hence Distance = 343 m/s × 5 s = 1715 m

To check, we compare the time it would take for the light to cover 1715 m

That is Time = \frac{Distance}{Speed} =  \frac{1715}{299,792,000} = 0.00000572 \, s which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.

Therefore, the distance of the students from the factory is approximately 1,715 m

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8 0
3 years ago
What is the mass of an object that has an acceleration of 2.63 m/s^2 when an unbalanced force of 112 N is applied to it?
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112/2.63= 42.586
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6 0
3 years ago
When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?
Inessa [10]

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6 0
3 years ago
In the movie Speed, a bus already moving faster than 55 mph will explode if the bus’ speed falls below 55 mph. Let say that the
kompoz [17]

Answer:

The bus moved after our girl Sandy passed out = S = 905.04 m

Explanation:

At  t = 0 sec              Vi = 80mph = 35.76 m/s

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According to the first equation of motion

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second equation of motion

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7 0
3 years ago
A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m
vfiekz [6]

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

5 0
3 years ago
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