A woman throws a baseball straight up into the air. what is the baseball's acceleration at its highest point?
1 answer:
After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward.
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is
at every point of the motion, and therefore also when the baseball is at its highest point.
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is
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Answer:
The period of rotation is
T=8.025s
Explanation:
The person is undergoing simple harmonic motion on the wheel
Given data
mass of the person =75kg
Radius of wheel r=16m
Velocity =8.25m/s
The oscillating period of simple harmonic motion is given as
T=(2*pi)/2=2*pi √r/g
Assuming that g=9.81m/s
Substituting our data into the expression we have
T=2*3.142 √ 16/9.81
T=6.284*1.277
T=8.025s
