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VARVARA [1.3K]
3 years ago
7

3x-6<=-3= Graph the inequality

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

6

Step-by-step explanation:

6

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Pancho built a cabinet shaped like a rectangular prism. The length of the base is 6 inches, and the width is 70 inches. What is
labwork [276]

Answer:

420in^2

Step-by-step explanation:

Given data

Length of base= 6 in

Widht of base= 70 in

We know that area= Length*Width

substitute

Area= 6*70

Area= 420 in^2

Hence the area of the base is 420in^2

3 0
3 years ago
For thanksgiving, you made 32 cupcakes. How many cupcakes were leftover if your family ate 3/4 of them?
Anvisha [2.4K]
All you need to do is divide 32 by 4.

32/4= 8

So, 3*8= 24 (that is 3/4 of the cupcakes)

32-24= 8

8 is the answer.

I hope this helps!

Brainliest answer is always appreciated! 
4 0
3 years ago
Read 2 more answers
Does anybody know the answer to these questions?
san4es73 [151]

Answer:

  1. 625,000 J

  2. 100 J

  4. 5 kg

  5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

__

1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

__

2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

__

4. KE = (1/2)<em>m</em>v²

  250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²

  (250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg

__

5. KE = (1/2)<em>m</em>v²

  2000 kg·m²/s² = (1/2)(800 kg)v²

  (2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

  v = √5 m/s ≈ 2.236 m/s

7 0
3 years ago
In ΔUVW, the measure of ∠W=90°, VW = 32 feet, and WU = 78 feet. Find the measure of ∠V to the nearest degree.
DanielleElmas [232]

Answer: 67.68^{\circ}

Step-by-step explanation:

Given

\angle W=90^{\circ}

VW=32\ ft

WU=78\ ft

from the figure, we can write

\Rightarrow \tan v=\dfrac{UW}{VW}\\\\\Rightarrow \tan v=\dfrac{78}{32}\\\\\Rightarrow \tan v=2.437\\\Rightarrow v=\tan^-1(2.437)\\\Rightarrow v=67.68^{\circ}

7 0
3 years ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
3 years ago
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