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Ne4ueva [31]
3 years ago
7

Dave has $15 to spend on an $8 dollar book and two birthday cards (c) for his friends. How much can he spend on each card if he

buys the same card for each friend?
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0
If Dave has 15 dollars and must spend 8 dollars of it on a book, then he will have 7 dollars left. If he then buys two of the same cards for his friends, the most he will be able to spend is half of 7 dollars for each of them, which will be 3 dollars and 50 cents. 
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prohojiy [21]
1/2x -5+2/3x =7/6x+4
First, you need to find the least <span>common </span>denominator between the 3 fractions....
2-3-6 The GCF is 6...
So to get rid of the fractions, multiply the whole equation by 2

6[ 1/2x -5+2/3x =7/6x +4 ]=
3x -30 +4x =7x +24

Now that we got rid of our fractions, we combine like terms...

3x -30 + 4x= 7x + 24
7x -30 = 7x + 24
-30 = 24 is not true

So, there is no solution

Hope this helps Nic
If you have seen this method in school before....
Maybe this will seem familiar
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4 years ago
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andrezito [222]
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3 0
4 years ago
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Answer:

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2 years ago
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Dovator [93]
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5 0
3 years ago
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