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kirza4 [7]
3 years ago
5

Daniel combines 6.42 liters of red paint with 6.87 liters of blue paint to make purple paint. He pours the paint equally into 3

containers, and has 2.64 liters of paint left over. How many liters of paint are in each container?
Mathematics
1 answer:
galben [10]3 years ago
4 0

Answer:

3.55 liters

Step-by-step explanation:

Daniel combines 6.42 liters of red paint with 6.87 liters of blue paint to make purple paint

= 6.42 + 6.87

= 13.29

He has 2.64 paints as left over

= 13.29-2.64

= 10.65

He pours the paint equally into three containers, therefore the amount of paint in each container can be calculated as follows

= 10.65/3

= 3.55 liters

Hence there are 3.55 liters in each container

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Answer:

X ~ B(n, p)

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Gre4nikov [31]
<h3><u>Answer:</u></h3>

\large\boxed{\pink{\sf \leadsto Value \ of \ LM \ is \ 11 \ units . }}

<h3><u>Step-by-step explanation:</u></h3>

A figure is given to us in which we can see two triangles one is ∆ MPL and other is ∆MPN .

<u>Figure</u><u> </u><u>:</u><u>-</u><u> </u>

\setlength{\unitlength}{1 cm}\begin{picture}(12,12)\linethickness{0.25mm}\put(0,0){\line(1,2){2}} \put(0.001,0){\line(1,0){4}}\put(2,0){\vector(0,1){5}}\put(4,0){\line( - 1,2){2}}\put(0,-0.4){$\bf L $}\put(2,-0.4){$\bf P$}\put(4,-0.4){$\bf N $}\put(2.2,4){$\bf M $}\put(2.8, - .4){$\bf 5 $}\put(1, - .4){$\bf 5 $}\put(3.4, 2){$\bf 11 $}\put(2.3,0){\line(0,1){.3}}\put(2.3,.3){\line( - 1,0){.3}}\end{picture}

\underline{\blue{\sf In\: \triangle MPL \ \& \ \triangle MPN :- }}

\qquad \bullet LP = PN = 5 \:\:(given) \\\\\qquad \bullet MP = MP \:\:(Common) \\\\\qquad \bullet \angle MPN = \angle MPL = 90^{\circ} \:\: (given)

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\orange{\bf \triangle MPL \cong \triangle MPN }

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