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2 years ago

Heloo hello HELPP FAST OR ILL DIE

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

4 0

Answer:

f(-7)= 21

Step-by-step explanation:

-(-7)^2-10(-7)

-7^2-10×-7

-49-10×-7

-49-(-70)

-49+70

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Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

$x = 3 + 4\sqrt{3} = 9.928(4s.f.)$

$x = 3 - 4\sqrt{3} = -3.928(4s.f.)$ (Length can't be negative)

∴ $x = 3 + 4\sqrt{3}$

3 0

2 years ago

Read 2 more answers

What is the Q1 of 1,2,3,5,7,9,10

arsen [322]

Answer: Q1 is the 2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve 7x- c= k for x. A. X = 7(k+C) B. x = 7(K-C) C. X = k+c/7 D. X= k-c/7

antoniya [11.8K]

Answer:

Step-by-step explanation:

you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.

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2 years ago

Will give 25 points and brainliest answer if correct

Norma-Jean [14]

Let $d$ be the common difference between terms in the sequence $\{a_n\}_{n\ge1}$ . Then

$a_{19}=-58$
$a_{20}=a_{19}+d$
$a_{21}=a_{19}+2d$
$\implies-164=-58+2d\implies d=-53$

The first term in the sequence, $a_1$ , satisfies

$a_2=a_1+d$
$a_3=a_1+2d$
$a_4=a_1+3d$
...
$a_{19}=a_1+18d$
$\implies-58=a_1+18(-53)\implies a_1=896$

So the explicit formula for the $n$ -th term in the sequence is

$a_n=a_1+(n-1)d\implies a_n=896-53(n-1)$

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3 years ago

Intro to Solving Literal Equations and Formulas Picture Below:

guapka [62]

Answer:

f/2 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

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2 years ago