Answer:
E = 20.03 J
Explanation:
Given that,
The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,
Voltage, V = 12 V
We need to find the energy delivered to the lightbulb filament during 2.00 s.
The energy delivered is given by :
. ....(1)
As,

As per Ohm's law, V = IR

Using formula (1).

So, the energy delivered to the lightbulb filament is 20.03 J.
Answer:
2400 calories
Explanation:
given,
diameter of pizza,d₁ = 6 inches
calories of the 6 inches pizza = 600 calories
diameter of large size of pizza, d₂ = 12 inches
calories of the 12 inches pizza = ?
Area of the 6 inches pizza
A₁ = π x 3² = 9 π
Area of the 12 inches pizza
A₂ = π x 6² = 36 π
Ratio of 12 inch pizza to 6 inches
=
=
calories of the pizza

x = 2400 calories
Pizza of 12 inches is of calories is equal to 2400 calories
I believe the k value represents the D. Stiffness of the spring.