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PtichkaEL [24]
2 years ago
12

What is the molar mass of carbon (C)?

Chemistry
2 answers:
stira [4]2 years ago
7 0

The molar mass of carbon (C) is 12.0107 u.

Alexxx [7]2 years ago
4 0

Answer:

Explanation:

The answer is 12.0107 u

Hope it helped you.

Plz mark me brainliest.

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Use electron configurations to account for the stability of the lanthanide ions Ce⁴⁺ and Eu²⁺.
Citrus2011 [14]

Answer:

Explanation:

 The Ce metal has electronic configuration as follows

[Xe] 4f¹5d¹6s²

After losing 4 electrons , it gains noble gas configuration ,. So Ce ⁺⁴ is stable.

Eu  has electronic configuration as follows

[ Xe ] 4 f ⁷6s²

[ Xe ] 4 f ⁷

Its outermost orbit contains 2 electrons so  Eu²⁺ is stable. Its +3 oxidation state is also stable.

Ce⁺²

7 0
3 years ago
Anabolic reactions _______ bonds, whereas catabolic reactions __________ bonds. A. decrease; increase. B. break; make C. weaken;
nexus9112 [7]

Answer:

The corrext answer is E. make; break

Explanation:

In living organisms, the metabolism is either anabolic or catabolic where anabolic metabolism is energy consuming and catabolic metabolism is eneegy releasesing. It should however be noted that anabolic reaction builds or biosynthesize new mollecular structures while catabolic reaction breaks down complex structure bonds into simple structures

The braking down of bonds in catabolic reations realeses energy to sustain the anabolic rection process for the formation of new bonds

6 0
3 years ago
How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?
Olin [163]

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound  = 1.43g

Molar mass of compound  = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

          Mass of sodium  = \frac{molar mass of Na}{molar mass of compound} x mass of sample

                                      = \frac{23}{23}  x 1.43g

                                       = 1.43g

Now find the number of moles of this amount of Na in the sample;

          Number of moles  = \frac{mass}{molar mass} = \frac{1.43}{23}  = 0.062mole

Now;

                    1 mole of substance  = 6.02 x 10²³ particles

                       0.062 mole of substance  =  0.062 x 6.02 x 10²³ particles

                                                                     = 3.74 x 10²² particles

7 0
3 years ago
a 32 gram radioactive sample has a half-life of 2 days how much of the original sample remains after 6 days
bixtya [17]
First, we will get the "n", the number of half lives, it is the elapsed time over the half life. In the problem, the time is measured in days, so we have 

6/2 = 3 

to get the ending amount of radioactive sample, we have

32g x (1/2)³ = 4 grams of radioactive sample ⇒ the amount left after 6 days


3 0
3 years ago
Generally, A loses electrons when reacting with nonmetals and gains electrons when reacting with metals. A is a(n):
lukranit [14]
Sorry I don’t exactly know I have exams rn I need points
4 0
2 years ago
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