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IRINA_888 [86]
3 years ago
10

What is the name of this hydrocarbon?

Chemistry
2 answers:
Ad libitum [116K]3 years ago
5 0
A. 2,3-dimethylpentane
Hoochie [10]3 years ago
4 0
2,3-dimethylpentane          
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What is the equation for figuring out the Atomic Mass
zhenek [66]

Answer:

Atomic mass = mass of protons + mass of neutrons

Explanation:

In an element atomic mass of an atom can be calculated by adding the mass of protons and neutrons

I hope this helps! :)

8 0
3 years ago
What is the formula for the compound formed by lead(II) ions and Chlorine ions?
Olenka [21]

Answer:

Pb(CrO4)Al2(SO4)3

Explanation:

3 0
3 years ago
A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
jeyben [28]

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

4 0
3 years ago
15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl
Readme [11.4K]

Answer:

The answer to your question is 41.6 g of AgCl

Explanation:

Data

mass of NH₄Cl = 15.5 g

mass of AgNO₃ = excess

mass of AgCl = 35.5 g

theoretical yield = ?

Process

1.- Write the balanced chemical reaction.

              NH₄Cl  +  AgNO₃   ⇒   AgCl  +  NH₄NO₃

2.- Calculate the molar mass of NH₄Cl and AgCl

NH₄Cl = 14 + 4 + 35.5 = 53.5 g

AgCl = 108 + 35.5 = 143.5 g

3.- Calculate the theoretical yield

                 53.5 g of NH₄Cl -------------------- 143.5 g of AgCl

                  15.5 g of NH₄Cl  -------------------    x

                         x = (15.5 x 143.5) / 53.5

                         x = 2224.25 / 53.5

                         x = 41.6 g of AgCl

8 0
3 years ago
If 400 Joules of work is done in 20 seconds, how much power was generated?
Sonbull [250]
To work this out you do 400÷20=20
5 0
3 years ago
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