Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). It is calculated by the expression:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q= 0.106 kJ= 106 J (being 1 kJ=1000 J)
- c= 25.4
- m= 28.5 g×
= 0.145 moles (being 196.967 g/mole the molar mass of gold) - ΔT= ?
Replacing:
106 J= 25.4 × 0.145 moles× ΔT
Solving:
ΔT=
ΔT= 28.78 C
The change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.
Learn more:
it is over 32 degrees Fahrenheit (freezing), and below 120 degrees Fahrenheit (boiling)
Answer:
Exothermic reaction: In exothermic reaction, energy is transferred to the surroundings, and the surrounding temperature increases, this is known as exothermic reaction. In other words energy exits in exothermic reaction. Some example of exothermic reactions are:
1) Neutralisation reaction.
2) Combustion reaction.
3) Some oxidation reaction.
Endothermic reaction: In endothermic reaction, energy is taken in from the surrounding, and the surrounding temperature decreases, this is known as endothermic reaction. In other words energy enters in endothermic reaction. Some example of exothermic reactions are:
1) Thermal decomposition.
2) Reaction between citric acid and sodium hydrogen carbonate.
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
To know more about mole ratio, visit the below link:
brainly.com/question/504601
The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?
Answer: The% m / m concentration of that solution is 6.66%.
Explanation:
Given: Mass of solute = 10 g
Mass of solvent = 150 g
Formula used to calculate the %m/m is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m / m concentration of that solution is 6.66%.
