Which of what? I don’t see a picture.
The solute is the substance that you put into water to dissolve.
Answer:
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
Explanation:
As we know
Amount of heat gained
Q = mc (T2-T1)
Here,
mass of water in cup 2 (m) = 79.10 grams
Temperature of water in cup 2 = 16.8 degree Celsius
Specific heat of water (c) = 4.186 J/(g °C)
Final Temperature of water in cup 2 = 23.2 degree Celsius
Substituting the given values, we get -
Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules
The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules
<h3>Answer:</h3>
Molar Mass = 56 g.mol⁻¹
<h3>Explanation:</h3>
Data Given:
Mass = 5.00 μg = 5.0 × 10⁻⁶ g
Number of Molecules = 5.38 × 10¹⁶ Molecules
Step 1: Calculate Moles of 1-Butene:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³
Number of Moles = 8.93 × 10⁻⁸ Moles
Step 2: Calculate Molar Mass of 1-Butene:
As,
Mole = Mass ÷ M.Mass
Solving for M.Mass,
M.Mass = Mass ÷ Mole
Putting values,
M.Mass = 5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol
M.Mass = 55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹
