There are 14 positions. There are 266 choices for the first juror, 265 for the second, 264 for the third, etc. 266*265*264*...*252=<span>5.93893009829e+33, or about 6,000,000,000,000,000,000,000,000,000,000,000 complete juries. Hope this helps!</span>
Answer:
Scott Street, Park Street,Oak Street
Step-by-step explanation:
Yes it does and it would also be true if the y was 4 or 6 because 2 plays into all of those but it would be false if it was something like 5
Answer: There are 5 candies of first type and 4 candies of second type.
Step-by-step explanation:
Since we have given that
Number of pieces of candy of first type = 15
Number of pieces of candy of second type = 20
We need to find the greatest number of pieces possible.
So, Greatest number of pieces = H.C.F. of 15 and 20 = 5
So, there are 5 greatest number of pieces possible.
Number of candies of first type in this piece = 
Number of candies of second type in this piece = 
Hence, there are 5 candies of first type and 4 candies of second type.