Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Hope this helps ;)
Answer:
11x + 8y
Step-by-step explanation:
(5x + 5y) + 3 ( 3 · 2x + 3y)
(5x + 5y) + (6x + 3y)
5x + 5y + 6x + 3y
5x + 6x + 5y + 3y
11x + 8y
Answer:
y = -1/2x +1
Step-by-step explanation:
The y intercept is 1 (this is where it crosses the y intercept)
(0,1) and (2,0) are two points on the line
The slope is given by
m = (y2-y1)/(x2-x1)
= (0-1)/(2-0)
= -1/2
The slope is -1/2
The slope intercept form is y = mx+b where m is the slope and b is the y intercept
y = -1/2x +1
"1 indicating a coupon and all other outcomes indicating no coupon"
Probability is (number of successful outcomes) / (number of possible outcomes)
Theoretical Probability of rolling a 1: 1/8
Experimental Probability of using coupons: 4/48 = 1/12
So, the experimental probability of a customer using a coupon (that is, 1/12) is smaller than the theoretical probability of rolling a 1 (that is, 1/8).
That "9 minutes" doesn't affect the outcome!
How many pieces of candy are in the bag at the beginning? How many of those are "fruit tart chews?" Write a fraction involving these 2 counts. Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20. What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together. Please show your work.
