DOES ANYONE KNOW WHAT HAPPENS IF YOU CLICK THE LINKS?
1 answer:
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In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
<h3>What is the variables about?</h3>Note that:
y=-8x+4
y-4=-8x
(y-4)/-8=x
Since the independent variable x is known, one can switch the variable labels and thus it will be:
y=(x-4)/-8
f^-1(x)=(x-4)/-8
This can be written again as:
f^-1(x)=(4-x)/8 :P
Thus one can say No, as he forgot to switch the variable labels after solving for the independent variable.
In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
See the first part of the question below
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.
Learn more about variable from
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The equation of a circle:
(h,k) - the coordinates of the centre
r - the radius
The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints
The centre of the circle is (2,5).
The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
The radius is 5.
(h,k) - the coordinates of the centre
r - the radius
The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints
The centre of the circle is (2,5).
The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
The radius is 5.