The bond order of Mg2 molecule is given by:
Mg2 = 4e⁻= 3σs(2e⁻) 3σs*(2e⁻) 3σp(0) 3πp(0e⁻) 3πp*(0e⁻)
3σp*(0e⁻)
Bond Order = ½[Σ (bonding e-) - Σ (antibonding e-)]
bo = ½[ {σs(2e⁻)} - {σs*(2e⁻)}] = 0
the bond between Mg2 molecules are ionic bonding and it
stable.
Answer:
A.) trans-2,3-dichloro-5-methyl-2-hexene
Explanation:
The proposed question and structure has been attached to this answer.
The<em> cis</em>- and <em>trans</em>- isomers are used to denote the alignment of the functional groups to the carbon chain side. From the diagram, we see that:
- the two chloro groups on the main compound are in opposite directions (-<em>trans</em>), and not the same sides (-<em>cis</em>)
- The bottom extended methyl group is on the 5th carbon as we count from left to right
- there's a total of 6 carbon atoms with 1 double bond on the second to third carbon.
Hence the name <u>trans-2,3-dichloro-5-methyl-2-hexene</u>