Acellus

Mathematics

1 answer:

ss7ja [257]3 years ago

6 0

Answer:

$AB = 3.6$

Step-by-step explanation:

Given

The attached graph

Required

Distance AB

From the graph:

$A = (-2,1)$

$B = (1,-1)$

The distance is:

$AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$AB = \sqrt{(-2 -1)^2 + (1- -1)^2}$

$AB = \sqrt{(-2 -1)^2 + (1+1)^2}$

$AB = \sqrt{13}$

$AB = 3.6$

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Which of the following shows the graph of y = 4x 3? on a coordinate plane, an exponential function starts at y = 3 in quadrant 2

ZanzabumX [31]

The graph of the linear equation y = 4x + 3 can be seen at the end of the answer.

<h3>How to find the graph of the given line?</h3>

Here we have the linear equation:

y = 4x + 3.

To graph it, we need to find two points that belong to the line, to do that, we evaluate in two different values of x. I will use x = 0 and x = 2.

When x = 0.

y = 4*0 + 3 = 3

So we have the point (0, 3).

When x = 2:

y = 4*2 + 3 = 8 + 3 = 11

So we have the point (2, 11)

Now we just need to graph these two points and connect them with a line. The graph of the linear equation is the one you can see below.

If you want to learn more about linear equations:

brainly.com/question/1884491

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