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Oduvanchick [21]
3 years ago
12

Witch ones are mathematical sentences? 5g=9 4x 8r=12 R+7=4 34 X=1

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0
R+7=4 I hope that this is correct answer

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The GCF of an odd number and an even number is always even
Oxana [17]
The answer is No it is not
7 0
3 years ago
Simplify please and show steps:<br><br> Sec (x) tan (x) csc (x) cot (x) sin (x) cos (x)
Airida [17]

Answer:

<h2>The answer is 1</h2>

Step-by-step explanation:

First of all transform the expression using trigonometric identities

That's

\sec(x)  =  \frac{1}{ \cos(x) }

\csc(x )   =  \frac{1}{ \sin(x) }

\cot(x)  =  \frac{1}{ \tan(x) }

So we have

\frac{1}{ \cos(x) }  \times  \tan(x)  \times  \frac{1}{ \sin(x) }  \times  \frac{1}{ \tan(x) }  \times  \sin(x)  \times  \cos(x)

Reduce the expression with tan x

We have

\frac{1}{ \cos(x) }   \times \cos(x)  \times  \frac{1}{ \sin(x) }  \times  \sin(x)

Reduce the expression with cos x

That's

1 \times  \frac{1}{ \sin(x) }  \times  \sin(x)

Reduce the expression with sin x

We have

1 \times 1

We have the final answer as

<h3>1</h3>

Hope this helps you

5 0
4 years ago
1. Given f(x) = 3x -4 and g(x)=-2x + 7. evaluate:<br> f(f(3))
hichkok12 [17]

Answer:

f(f(3))=11.....

hope it helps u

5 0
3 years ago
Read 2 more answers
Find the value of k so that the graph of the equation has the given y-intercept.
m_a_m_a [10]
Equation of a line is given by y = mx + b; where m is the slope and b is the y-intercept.
In the given equation, y = -13x + 56k; b = -10
56k = -10
k = -10/56 = -5/28
4 0
4 years ago
Please help 50 points!<br> Simplify the expressed
LenKa [72]

Answer:

Step-by-step explanation:

\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}  rewrite as multiplication

\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}  look to factor

\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}, finish factoring and simplify

2(x+3)

3 0
3 years ago
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