Answer:
0.04746
Step-by-step explanation:
To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes. Either use a table of z-scores or a calculator with probability distribution functions.
In this case I will use my old Texas Instruments TI-83 calculator. I select the normalcdf( function and type in the following arguments: :
normalcdf(-100, 5, 4, 0.6). The result is 0.952. This is the area under the curve to the left of x = 5. But we are interested in finding the probability that a conversation lasts longer than 5 minutes. To find this, subtract 0.952 from 1.000: 0.048. This is the area under the curve to the RIGHT of x = 5.
This 0.048 is closest to the first answer choice: 0.04746.
Answer:
4/3
Step-by-step explanation:
(4-8)/(2-5) = -4/-3 = 4/3
Answer:
x>-7
Step-by-step explanation:
Answer:
The mass of the ice block is 2116 grams ⇒ a
Step-by-step explanation:
The formula of density is 
, where m is the mass and V is the volume
To find the mass from this formula multiply both sides by V,
then m = p.V
∵ The density of ice is approximately 0.92 g/cm³
∴ p = 0.92
- That means the mass of 1 cm³ is 0.92 g
∵ The volume of an ice block is 2300 cm³
∴ V = 2300
- Use the formula of the mass
∵ m = p.V
- Substitute the values of p and V in it
∴ m = (0.92)(2300)
∴ m = 2116 grams
The mass of the ice block is 2116 grams
