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Brilliant_brown [7]
3 years ago
10

Rachel's Designs has 2,000 shares of 7%, $50 par value cumulative preferred stock issued at the beginning of 2019. All remaining

shares are common stock. Due to cash flow difficulties, the company was not able to pay dividends in 2019 or 2020. The company plans to pay total dividends of $23,000 in 2021. How much of the $23,000 dividend will be paid to preferred stockholders and how much will be paid to common stockholders?
Preferred dividends in arrears for 2019 and 2020?
Preferred dividends for 2021?
Total Dividends?
Business
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

Dividend of preferred shares = No of shares * Dividend percent * Par value of shares = 2,000 * 7% * $50 = $7,000

Hence, dividend in arrears for the year 2019 and 2020 is $14,000 ($7,000+$7,000). Dividend for 2021 is $7,000

Description                                                                             Amount

Preferred dividend in arrear for the year 2019 and 2020  $14,000

Add: Preferred dividend for the year 2021                          <u>$7,000</u>

Total preferred dividend                                                       $21,000

Less: Total dividend                                                               <u>$23,000</u>

Dividend for common shareholder                                     (<u>$2,000)</u>

Hence, dividend paid for cumulative preferred share in the year 2021 is $21,000 and the amount paid for common shareholders is $2,000

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7 0
2 years ago
A company produces very unusual CD's for which the variable cost is $ 17 per CD and the fixed costs are $ 30000. They will sell
Alika [10]

Answer:

Explanation:

Let we assume the number of CD produced be X

So, the total cost would be

C = Fixed cost + variable cost × number of CD produced

   = $30,000 + $17X

For total revenue, it would b

R = $63X

For total profit, it would be

P = Selling cost per CD  × number of CD produced - variable cost per CD × number of CD produced - fixed cost

= $63X - $17X - $30,000

= $46X - $30,000

For number of CD, it would be

0 = $46X - $30,000

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4 0
2 years ago
Watauga Office Supply paid state unemployment taxes of $168.00. What is the entry to journalize the payment of the unemployment
alisha [4.7K]

Answer:

State unemployment tax payable A/c Dr $168

         To Cash A/c $168

(Being state unemployment taxes are paid for cash)

Explanation:

The journal entry to record the payment of the unemployment taxes is shown below:

State unemployment tax payable A/c Dr $168

         To Cash A/c $168

(Being state unemployment taxes are paid for cash)

For recording this transaction, we debited the State unemployment tax payable as it increase the liability and cash account should be credited as it reduce the current assets

7 0
3 years ago
At an activity level of 9,300 machine-hours in a month, Falks Corporation’s total variable production engineering cost is $829,5
Neko [114]

Answer: $109.3 per machine hour

Explanation: We can compute total production engineering cost per hour by using following equation :-

=cost\:per\:machine\:hour=\frac{fixed\:cost\:+\:variable\:cost}{total\:machine\:hours}

but first we need to calculate variable cost at 9600 hours :-

=\$829,560\times\frac{9600hr}{9300hr}

       = $856,320

now,

=cost\:per\:machine\:hour=\frac{\$192,960+\$856,320}{9600hr}

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4 0
3 years ago
A mining company owns two mines, each of which produces three grades (high, medium, and low) of ore. The company has a contract
sashaice [31]

Answer:

They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.

Explanation:

The formulation of the linear programming is:

Objective function:

C=200M_1+160M_2

Restrictions:

- High-grade ore: 6M_1+2M_2\geq12

- Medium-grade ore: 2M_1+2M_2\geq8

- Low-grade ore: 4M_1+12M_2\geq24

- No negative hours: M_1,M_2\geq0

We start graphing the restrictions in a M1-M2 plane.

In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.

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Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.

(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).

The solution is for the point (M1=1, M2=3), with a cost of C=$680.

The cost function graph is attached.

7 0
3 years ago
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