Answer:
a) W = - 318.26 J, b) W = 0
, c) W = 318.275 J
, d) W = 318.275 J
, e) W = 0
Explanation:
The work is defined by
W = F .ds = F ds cos θ
Bold indicate vectors
We create a reference system where the x-axis is parallel to the ramp and the axis and perpendicular, in the attached we see a scheme of the forces
Let's use trigonometry to break down weight
sin θ = Wₓ / W
Wₓ = W sin 60
cos θ = Wy / W
Wy = W cos 60
X axis
How the body is going at constant speed
fr - Wₓ = 0
fr = mg sin 60
fr = 15 9.8 sin 60
fr = 127.31 N
Y Axis
N - Wy = 0
N = mg cos 60
N = 15 9.8 cos 60
N = 73.5 N
Let's calculate the different jobs
a) The work of the force of gravity is
W = mg L cos θ
Where the angles are between the weight and the displacement is
θ = 60 + 90 = 150
W = 15 9.8 2.50 cos 150
W = - 318.26 J
b) The work of the normal force
From Newton's equations
N = Wy = W cos 60
N = mg cos 60
W = N L cos 90
W = 0
c) The work of the friction force
W = fr L cos 0
W = 127.31 2.50
W = 318.275 J
d) as the body is going at constant speed the force of the tape is equal to the force of friction
W = F L cos 0
W = 127.31 2.50
W = 318.275 J
e) the net force
F ’= fr - Wx = 0
W = F ’L cos 0
W = 0
I also agree to A. The force will always pull back a lot deals with gravitational pull
In order to answer this, we would need to know
the half-life of ⁴⁰K. Perhaps when you look that up,
you'll be able to answer this on your own.
Answer:
The amount by which the second filter reduces the intensity of light emerging from the first filter is
z = 0.60
Explanation:
From the question we are told that
The angle between the axes is ![\theta = 41^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2041%5Eo)
The intensity of polarized light that emerges from the second filter is mathematically represented as
![I= I_o cos^2 \theta](https://tex.z-dn.net/?f=I%3D%20I_o%20%20cos%5E2%20%5Ctheta)
Where
is the intensity of light emerging from the first filter
![I = I_o [cos(41.0)]^2](https://tex.z-dn.net/?f=I%20%20%3D%20I_o%20%20%5Bcos%2841.0%29%5D%5E2)
![I =0.60 I_o](https://tex.z-dn.net/?f=I%20%20%3D0.60%20I_o)
This means that the second filter reduced the intensity by z = 0.60