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malfutka [58]
3 years ago
14

Motivate me for my exam​

Physics
1 answer:
Brut [27]3 years ago
8 0

Answer:

if i can pass, you can too :)

Explanation:

its super inspiring cuz im a dum‎‎b‎‎a‎‎ss

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Astar is 10 light years away from the earth. Suppose it brightens up suddenly today, after how long can we see this change?
Blababa [14]

The phrase "light year" is a <u><em>distance</em></u> ... it's the distance that light travels through vacuum in one year.

When you look at an object located 1 light year away from you, you see it as it was 1 year ago.

If a star located 10 light years away from us suddenly brightens, or dims, or explodes, we see the event <em>10 years later.</em>

7 0
3 years ago
3 Points
AleksAgata [21]

Answer:

B.C. D. G.

Explanation:

A vector quantity, has both magnitude and direction. A tip to remember is if you can add a direction to it! You wouldnt say 30 pounds north, but you would say 30 mph north.

<em>I hope this helped! Comment if you have any questions! :)</em>

3 0
3 years ago
The sum of two or more vectors is called a<br> vector.<br> Answer kere
Sonbull [250]

Answer:

Resultant vector is the sum of two or more vectors

8 0
3 years ago
Read 2 more answers
Help please, i don't know what the answer is but i accidently clicked D .....
GaryK [48]

Answer:

You are right correct option is D.

4 0
3 years ago
A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of
777dan777 [17]

Answer:

The correct answer will be:

(a) 27.3 m/s

(b) 3.8 s

Explanation:

According to the question:

Acceleration,

a= 4.2 \ m/s^2

Time,

t = 6.5 \ s

(a)

The gazelles top speed will be:

⇒  V_{max} = at

             =4.2\times 6.5

             =27.3 \ m/s

or,

             = 27 \ m/s

(b)

As we know,

s = 30 m

Now,

⇒  s = \frac{1}{2} at^2

or,

⇒  t=\sqrt{\frac{2s}{a} }

On putting the given values, we get

       =\sqrt{\frac{2\times 30}{4.2} }

       =\sqrt{\frac{60}{4.2} }

       =3.78 \ s

or,

       =3.8 \ s

5 0
2 years ago
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