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hammer [34]
3 years ago
6

The nucleus contains both protons and electrons True or false

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer: False

Explanation: The nucleus of an atom only contains the protons and neutrons.

The electrons are not found in the nucleus,

they are orbiting the nucleus in different shells.

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Balance this chemical equation<br><br> __K+__H2O&gt;&gt;&gt; __KOH+__H2
Anestetic [448]

Answer:

2K+2H2O=2KOH+H2

Explanation:

Try to ensure there is same number of reactants as products

3 0
3 years ago
Alkenes can be converted to alcohols by hydroboration–oxidation. Draw a structure showing one of the alcohols formed in the foll
makkiz [27]

Answer:

  1. CH3CH2CH2CH2CHCH2OH  Hexanol

Explanation:

          Hydroboration reaction of Hexene yields Hexanol

5 0
3 years ago
I'd: 9872093250, password: qqqqq, join the meeting​
yanalaym [24]
No but give me thanks
4 0
2 years ago
A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask a
Eva8 [605]

Answer:

1.7 mL

Explanation:

<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>

Step 1: Calculate [H⁺] in the dilute solution

We will use the following expresion.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M

Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.

Step 2: Calculate the volume of the concentrated HCl solution

We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL

3 0
3 years ago
What is the mass (in grams) of 9.79 × 1024 molecules of methanol (CH3OH)?
nevsk [136]
We will use this formlula: Mass in grams = Number of moles x Molecular mass of 1 mole.

Since, we know the avagadro number is 6.02 x 10²³, we only have two unknown values left which are the molecular mass of CH3OH and its mole.

Molecular Mass: C = 12, H= 1, O = 16, since we have C=12, H4 = 4, O = 16, we will add them up: 12 + 4 + 16 =32

We know that one mole of anything = 6.02 x 10²³.
So we will use this formula to find the mole of methanol: Number of moles = Number of molecules / Avagadro number

Number of moles of CH3OH = (9.79 x 10^24)/6.02 x 10²³) =  16.263 moles.

Now we know that the molecular mass = 32 and the mole is = 16.263.

Now we can find its mass by using this formula: <span>Mass in grams = Number of moles x Molecular mass of 1 mole.
</span>
Mass in grams = 16.263 x 32 = 520g






6 0
3 years ago
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