Answer:
a) 2.01 g
Explanation:
- Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃
First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:
- 0.0302 mol AgNO₃ *
= 0.0151 mol Na₂CO₃
So the remaining Na₂CO₃ moles are:
- 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃
Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:
- 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃
The closest answer is option a).
<span>when density in g/ml
9.86ml CH3COOH (X g/1ml) = g
1.049g/ml
9.86ml (1.049g/1ml) = 10.343 g
hope it helps
</span>
Answer:
<h3><em>A is most likely your correct answer</em></h3>
Explanation:
A. Hills Covered with dry brush- this is most likely correct
b. Hills covered in lush grass- incorrect, because it is LUSH grass which would require lots of rain.
c. Flat lands with little grass- incorrect because grasslands DO have lots of grass.
D- incorrect because grasslands typically do NOT have rocky mountains <u>but are generally flatlands with grass</u>
<u />
<h3>I am so sorry if this is wrong, I am just using common knowledge. TREASURE EVERY MOMENT AND HAVE AN AMAZING DAY!! ;)</h3>
Answer:
well if you ever do neeed help im here
Explanation: