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worty [1.4K]
4 years ago
6

A chemist determines by measurements that 0.0200 moles of chlorine gas participate in a chemical reaction. Calculate the mass of

chlorine gas that participates.
Chemistry
1 answer:
Schach [20]4 years ago
8 0

Answer:

1.4200 g

Explanation:

The chlorine gas has a molecular formula Cl2. In table periodic, the molar mass of one atom of chlorine is 35.5 g/mol, so the molar mass of Cl2 is 71 g/mol.

Molar mass, mass and number of moles are related by the equation below:

n = \frac{m}{MM}

Where n is the number of moles, m is the mass, and MM is the molar mass of the compound.

So, for 0.0200 moles of Cl2 produced:

0.0200 = \frac{m}{71}

m = 71x0.0200

m = 1.4200

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Caffeine, a stimulant in coffee and tea, has a molar mass of 194.19 g/mol and a mass percentage composition of 49.48% C, 5.19% H
lozanna [386]

Answer : The molecular formula of a caffeine is, C_8H_{10}N_4O_2

Solution :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 49.48 g

Mass of H = 5.19 g

Mass of N = 28.85 g

Mass of O = 16.48 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.48g}{12g/mole}=4.12moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.19g}{1g/mole}=5.19moles

Moles of N = \frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{4.12}{1.03}=4

For H = \frac{5.19}{1.03}=5.03\approx 5

For N = \frac{2.06}{1.03}=2

For O = \frac{1.03}{1.03}=1

The ratio of C : H : N : O = 4 : 5 : 2 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_4H_5N_2O_1=C_4H_5N_2O

The empirical formula weight = 4(12) + 5(1) + 2(14) + 16 = 97 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{194.19}{97}=2

Molecular formula = (C_4H_5N_2O)_n=(C_4H_5N_2O)_2=C_8H_{10}N_4O_2

Therefore, the molecular of the caffeine is, C_8H_{10}N_4O_2

5 0
3 years ago
Based on the kinetic molecular theory, which of the following statements is correct about the particles in a sample of gas at a
fgiga [73]

Answer:

There is a lot of empty space between them.

Explanation:

The kinetic molecular theory postulates that a substance is made up of tiny particles called molecules. The molecules of a gas are in constant random motion and collide elastically with each other. They also collide with the walls of the container.

The magnitude of intermolecular forces of attraction between gas molecules is very small. Hence gas molecules are largely apart with a lot of empty space between gas molecules.

8 0
3 years ago
A compound containing oxygen and group 16 and/or group 17 elements contains one of the following elements. The compound dissolve
Sphinxa [80]

Explanation:

pottassium  its one of covalent bond

3 0
3 years ago
Read 2 more answers
What exactly is an explosion
yulyashka [42]
An explosion is a sudden release of enormous energy, being released all at once, particularly from a trapped container. The enormous amount of energy being released expands rapidly, more than the air can adjust around them, which makes the sound you hear and the fast light that you see is the energy being released.
6 0
3 years ago
Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2. (2
katen-ka-za [31]

Percent yield is 23.11 % when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2.

Explanation:

Balanced equation for the chemical reaction:

2C8H18 + 25O2 → 16CO2 + 18H2O

data given:

CO2 formed (actual yield)  = 162.8 grams

mass of oxygen = 218 grams

16 moles of CO2 formed when 5 moles of oxygen reacted

3.6 moles of CO2 formed when 6.8 moles of oxygen reacted.

In the reaction 16 moles of CO2 will have 44.01 x 16

                                      theoretical yield of CO2    = 704.16 grams

percent yield = \frac{actual yield}{theoritical yield}   x100

         putting the values in the above equation

percent yield = \frac{162.8}{704.16}  x 100

                       = 0.23 x 100

                           = 23.11 %

Percent yield is 23.11 %.

   

7 0
3 years ago
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