Answer:
1. CaCO3 + 2HCl —> CaCl2 + H2O + CO2
2. Mg(OH)2 + 2HCl —> MgCl2 + 2H2O
3. Na2CO3 + 2HCl —> 2NaCl + H2O + CO2
Answer:
The nuclear fuel used in a nuclear reactor needs to have a higher concentration of the U 235 isotope than that which exists in natural uranium ore. U235 when concentrated (or "enriched") is fissionable in light-water reactors (the most common reactor design in the USA).
Explanation:
Answer:
The answer is 11 electron and 11 protons respectively
Explanation:
Since the sodium is in it neutral state, number of electron is the same as the number of proton, which is 11.
The percent yield of the reaction : 89.14%
<h3>Further explanation</h3>
Reaction of Ammonia and Oxygen in a lab :
<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>
mass NH₃ = 80 g
mol NH₃ (MW=17 g/mol):

mass O₂ = 120 g
mol O₂(MW=32 g/mol) :

Mol ratio of reactants(to find limiting reatants) :

mol of H₂O based on O₂ as limiting reactants :
mol H₂O :

mass H₂O :
4.5 x 18 g/mol = 81 g
The percent yield :
