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3 years ago

Calculate the nuclear binding energy in mega-electronvolts (MeV) per nucleon for Th232. Th232 has a nuclear mass of 232.038 amu.

Chemistry

1 answer:

SOVA2 [1]3 years ago

3 0

Answer:

1720 MeV

Explanation:

Thorium has 90 protons and 142 neutrons

The mass of each proton is 1.007277 amu

The mass of each neutron is 1.008665 amu

The mass of 90 protons is 90 * 1.007277 amu = 90.65493 amu

The mass of 142 neutrons is 142 * 1.008665 amu = 143.23043 amu

Total calculated mass of nucleons = 90.65493 amu + 143.23043 amu = 233.88536

Mass defect = 233.88536 amu - 232.038 amu = 1.84736 amu

We convert from amu to MeV using the conversion factor of 931

Binding energy = 1.84736 amu * 931 = 1720 MeV

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The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its el

Nataly [62]

The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element % Atomic mass Relative no. of atoms Simplest whole ratio

C 83.87 12 $\frac{83.87}{12}$ = 6.98 $\frac{6.98}{0.25}$ = 3

H 11.99 1 $\frac{11.99}{1}$ = 11.09 $\frac{11.09}{0.25}$ = 4

O 4.14 16 $\frac{4.14}{16}$ = 0.25 $\frac{0.25}{0.25}$ = 1

Thus the empirical formula is C₃H₄O₁.

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = $\frac{\text{Molecular weight}}{\text{Empirical formula weight}}$

= $\frac{386.64}{56}$

= 7

Molecular formula = Empirical formula × n

= 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

#SPJ4

7 0

2 years ago

A pea plant has two dominant alleles for plant height – tall. We say that this plant is?:

Irina-Kira [14]

I think the answer is codominant??

3 0

3 years ago

Translation: Explain the importance of energy levels,

tigry1 [53]

Answer: Formation of a stable Duplet or Octet structure

Explanation:

Energy levels refers to the definite amount of energies that electrons can have when occupying specific orbitals.

Examples are:

Level 1 as in 1s

Level 2 as in 2s, 2p

Level 3 as in 3s 3p 3d

Level 4 as in 4s 4p 4d 4f

Level 5 as in 5s .......

Level 6 as in 6s .........

Electrons can be excited to higher energy levels by absorbing energy from the surroundings during chemical reactions and so forming chemical bonds like ionic, covalent etc.

A perfect example is Sodium (Na) and Chlorine (Cl) in Sodium chloride (NaCl)

Sodium has atomic number of 11, so energy level is 1s2, 2s2 2p6, 3s1

Chlorine has atomic number of 17, so energy level is 1s2, 2s2 2p6, 3s2 3p5

You will notice that the both Na and Cl, has electrons in the energy level 3. Then, the bond formed must be one that lead to the formation of a OCTET structure: as in Na gives off its 3s1 electron TO Cl.

Thus, Cl now becomes 1s2, 2s2 2p6, 3s2 3p6 - an OCTET STRUCTURE (with completely filled outershell and full energy level 3) in NACl.

So, a duplet or Octet structure is the answer

8 0

4 years ago

How does the sun impact the speed of the water cycle?

IceJOKER [234]

the sun makes it evaporate quicker if it is there for longer

8 0

3 years ago

a sample of ammonia contains 9g hydrogen and 42g nitrogen. another sample contains 5g hydrogen .calculate the amount of nitrogen

balandron [24]

9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen

$9x=42 \cdot 5 \\
9x=210 \\
x \approx 23.33$

The mass of nitrogen in the second sample is 23.33 g.

4 0

4 years ago