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3 years ago

1.The movement of particles from a less crowded area to a more crowded area requires

Chemistry

1 answer:

Harrizon [31]3 years ago

7 0

1. Energy as particles can't move without kinetic (movement) energy
2. I think it's Diffusion and Active Transport

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An energy profile for the reaction A⇌B (left), and the change in concentration of B as a function of time (right), with and with

RoseWind [281]

Answer:

<em>What quantity dictates the speed of a reaction?</em> The activation energy

Explanation:

According to the collision theory, when molecules collide, they must overcome an energy barrier for the reaction to take place. This energy, known as activation energy, is represented by the difference in energy between the initial state and the transition state. The higher the activation energy, the slower the reaction. That's why catalysts reduce the activation energy to accelerate the reaction.

3 0

4 years ago

Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For ro

Nata [24]

Answer:

$\boxed{\text{199 mL}}$

Explanation:

1. Calculate the moles of HCl

$n = \text{25.4 g} \times \dfrac{\text{1 mol}}{\text{36.46 g}} = \text{0.6967 mol}$

2. Calculate the volume of dilute HCl

$\begin{array}{rcl}\text{Molar concentration}& =& \dfrac{\text{moles}}{\text{litres}}\\\\3.50 & = & \dfrac{0.6967}{V}\\\\3.50V & = & 0.6967\\\\V & = & \dfrac{0.6967}{3.50}\\\\V & = & \text{0.199 L} =\textbf{199 mL}\end{array}\\\text{The volume of muriatic acid needed is }\boxed{\textbf{199 mL}}$

3 0

3 years ago

Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and

alisha [4.7K]

H₂O would be the limiting reactant.

Balanced chemical equation:

6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

No. of moles of H₂O = Given mass/ Molar mass

= 238 / 18 = 13.22 moles

Moles of H₂O = 13.22

According to the balanced chemical equation

6 moles of CO₂ react with 6 moles of H₂O

So the reactant that has less number of moles will be consumed first.

As the No. of moles of H₂O < No. of moles of CO₂

So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

Learn more about limiting reactant here brainly.com/question/14222359

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7 0

2 years ago

Solve for x 5 to the power 2 x + 4 - 25 to the power x - 1 is equals to

Dafna11 [192]

Answer:

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4 0

3 years ago

Read 2 more answers

Wheen 56j of heat are added to 11g of liquid, its temperature rises from 10.4 degrees celsius to 12 degrees celsius. What is the

svetoff [14.1K]

$c = 3.2 \; \text{J} \cdot \text{kg}^{-1} \cdot \text{K}^{-1}$

Energy change $Q = 56 \; \text{J}$
Mass being heated $m = 11 \; \text{g}$
Temperature change $\Delta T = 12 - 10.4 = 1.6\;^{\text{o}}\text{C}$ which is the same as $1.6 \;\text{K}$ .

Heat capacity measures the energy required to raise the temperature of a unit mass of a substance by a unit degree. Therefore

$c = Q / (m \cdot \Delta T) = 56/(11 \times (12 - 10.4)) = 3.2 \; \text{J} \cdot \text{kg}^{-1} \cdot \text{K}^{-1}$

7 0

4 years ago

Read 2 more answers