1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ss7ja [257]
3 years ago
6

A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.

He notes the temperature of the pool, 170 C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 500. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.96 g Using only the information above, can you calculate yes the solubility of X in water at 17.0 C? If you said yes, calculate it. Be sure your answer has a unit symbol and 3 O no significant digits.
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

The solubility of X in water at 17°C is 0.110 g/mL.

Explanation:

The water of a rock pool lined with mineral crystals is a <em>saturated solution</em> of said mineral, this means the concentration of X in those 36 mL is the solubility of compound X in water at 17 °C.

  • This means<u> it is possible to calculate said solubility</u>.

The dilution of the sample is not relevant, nor is that 500 mL volume. What's important is that 3.96 g of X form a saturated solution with 36.0 mL of water, so the solubility is:

  • 3.96 g / 36.0 mL = 0.110 g/mL
You might be interested in
A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and
IrinaK [193]

Answer:

34.02 g.

Explanation:

Hello!

In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol

So probably, the gas may be H₂S.

Best regards!

6 0
3 years ago
Find the molecular mass of MgSO4 ​
rewona [7]
120.38 g/mol is the answer
7 0
3 years ago
Read 2 more answers
Draw the structural formula for fatty acid C 18:2 9 a 12a
qwelly [4]

Answer:

............................................................................

Explanation:

7 0
3 years ago
If gold gets hot enough it will melt, what type of change is this?
SashulF [63]
A.
Physical change
Step by step explanation;:)
8 0
3 years ago
Read 2 more answers
An element in group 7 on the periodic table most likely has which physical property?
larisa86 [58]

Answer:

They are most likely solid

Explanation:

solid is a physical property

3 0
3 years ago
Other questions:
  • The freezing point of diet soda is higher than the freezing point of regular soda, but lower than 0 degrees celcius, the freezin
    6·1 answer
  • Find the mass in 6.2 miles of lithium bromide, show work
    5·1 answer
  • The larger the pH scale value, the:
    8·1 answer
  • Will give brainlest once two answer!!!
    7·1 answer
  • In a sample containing a mixture of only these gases at exactly one atmosphere pressure, the partial pressures of carbon dioxide
    11·1 answer
  • A generator is not required to generate electrical energy when which of the following energy sources is used?
    14·2 answers
  • All minerals on the mohs hardness scale are hard enough to scratch a piece of glass is it true or false
    8·2 answers
  • How many moles are in 4.3 x 1024 molecules of H20?
    9·1 answer
  • 33. A basketball bounces on the gym floor nine times and finally comes to a rest. Which of these BEST explains why the
    10·1 answer
  • Which of the following is a stock exchange in the United States?(1 point)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!