Answer:
at least 5
Step-by-step explanation:
<u><em>If the question was similar to the one given below </em></u>
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?
<em><u>The answer would be as follows</u></em>
If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
4C2= 6 ways to use these letters and the comma
If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
5C2= 10 ways to use these letters and the comma
If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
6C2= 15 ways to use these letters and the comma
We need the least number of the alphabets to assign codes to 12 participants.
So the least number of alphabets is 5 because it can give codes to at least to 12 people .
Pair of alphabets + distinct letter ≥ 12
5 + 1 ≥ 12
6c2 ≥ 12
15 ≥ 12
Answer:
Rewrite the first equation as x = 36 – 3y.
Step-by-step explanation:
x + 3y = 36 (1)
4x + 5y = 9 (2)
Using substitution method
From (1)
x = 36 - 3y
Substitute x = 36 - 3y into (2)
4x + 5y = 9
4(36 - 3y) + 5y = 9
144 - 12y + 5y = 9
- 12y + 5y = 9 - 144
-7y = -135
y = -135 / -7
y = 19.3
There is an error with the second equation, 4x + 5y can not be equal to 9
Nevertheless, the first step when solving by substitution is:
Rewrite the first equation as
x = 36 – 3y.
Answer:
The coordinates of M are (2,-8)
Step-by-step explanation:
The coordinates of the point that divides the line segment joining
to 
in the ratio m:n is given by:
If A is at (-4,-2) and B is at (4. -10) and the ratio is 3:1.
Then
The coordinates of M are (2,-8)
Answer:
$2158.8
Step-by-step explanation:
x/89,950= 2.4/100
89,950(2.4)= 215880
215880/100 gets you 2158.8. hope this helped
