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nexus9112 [7]
3 years ago
5

Why is ice cold water rather than room temperature or warm water used to wash the remainder of the benzoic acid out of the beake

r?
Chemistry
1 answer:
sergiy2304 [10]3 years ago
7 0

Filtration, is a chemical process where you are separating a precipitate from a solution.

As a general rule:

"Solubility of compounds decrease with the increasing of temperature" as you can see in the graph

Now, if you want to recover benzoic acid from an aqueous solution, the better option would be with Ice cold water because its solubility will be lower producing more precipitate.

Learn more about this process in:

brainly.com/question/14918321

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What is the subscript present in NaCl?
jonny [76]

Answer:

NaCl or sodium chloride, is commonly known as table salt. ... Subscripts show the ratio of atoms of different elements in the compound. Since there are four hydrogen atoms in the molecule, the subscript 4 follows the symbol for hydrogen.

Explanation:

3 0
4 years ago
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What does a tornado warning indicate
UNO [17]

Answer:

Tornado warnings indicate imminent danger to life and property.

Explanation:

A tornado has been in sight or will come.

4 0
3 years ago
Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li
Lera25 [3.4K]

Answer:

4.41

Explanation:

Step 1: Write the balanced equation

CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

Step 2: Calculate the respective concentrations

[CO]_i = \frac{0.500mol}{5.00L} = 0.100M

[H_2]_i = \frac{1.500mol}{5.00L} = 0.300M

[H_2O]_{eq} = \frac{0.198mol}{5.00L} = 0.0396M

Step 3: Make an ICE chart

        CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

I       0.100      0.300        0            0

C         -x           -3x          +x          +x

E    0.100-x    0.300-3x     x            x

Step 4: Find the value of x

Since the concentration at equilibrium of water is 0.0396 M, x = 0.0396

Step 5: Find the concentrations at equilibrium

[CO] = 0.100-x = 0.100-0.0396 = 0.060 M

[H₂] = 0.300-3x = 0.300-3(0.0396) = 0.181 M

[CH₄] = x = 0.0396 M

[H₂O] = x = 0.0396 M

Step 6: Calculate the equilibrium constant (Kc)

Kc = \frac{[CH_4] \times [H_2O] }{[CO] \times [H_2]^{3} } = \frac{0.0396 \times 0.0396 }{0.060 \times 0.181^{3} } = 4.41

3 0
4 years ago
giving the incomplete equation 2N2O5 (g) which set of products completes and balances the incomplete equarion
a_sh-v [17]

Answer:

The complete question is as follows

Given the incomplete equation: 2 N2O5(g) ==>  Which set of products completes and balances the incomplete equation?

A)2 N2(g) + 3 H2(g)

B)2 N2(g) + 2 O2(g)

C)4 NO2(g) + O2(g)

D)4 NO(g) + SO2(g)

The correct option is C) 4NO2(g) + O2(g)

Explanation:

Note that the products should be NO2 and O2 since the reactant is entirely made up of N and O. option A is not correct as hydrogen cannot emerge as a product in this reaction. Matter can never be created or be destroyed bu can only change in a chemical reaction. Option D is not also correct for the same reason.

Option B is not correct since it did not balance the number of atoms of O and N in the reactant side of the equation.

The option C) 4NO2(g) + O2(g) is therefore the right option since it balances both the elements and the number of atoms of the elements present.

7 0
4 years ago
Formation of hydrogen bonds requires hydrogen atoms and what else? polar covalent bonds water ionic bonds oxygen
jeyben [28]

Formation of hydrogen bonds require hydrogen atoms and Oxygen atoms, fluorine atoms, or nitrogen atoms.

Hydrogen bond is a special case of dipole-dipole force of attractions. Here there are two polar molecules in which one of them has hydrogen atom with partial positive charge on it and the other molecule can be O, F or N with partial negative charge. Since, these dipole-dipole force of attractions are stronger than other dipole-dipole force of attractions we name it as Hydrogen bonds.

Some of the examples where hydrogen bonding is present are- H₂O, HF, NH₃ etc

Since, Hydrogen bonds are a type of dipole-dipole forces of attraction, they are present in polar covalent molecules.

To know more about Hydrogen bonds here

brainly.com/question/10904296

#SPJ4

3 0
1 year ago
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