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3 years ago

10

Rock and mineral fragments come from __________ and are small particles of sediment such as

______________________________.

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

Rocks can be simply defined as the aggregates of various minerals, and these broken rock fragments and mineral grains are formed from the weathering of rocks. Weathering refers to the breakdown of rocks due to the occurrence of various geological processes that are initiated by the agents such as wind, water and ice.

The weathering process leads to the formation of sediments of variable size and shape, and these are such as pebbles, sand, silt and clay particles.

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Help please!!!!!!!!!!!!!!!!

Romashka-Z-Leto [24]

Answer:

A....................

3 0

2 years ago

Part A: Three gases (8.00 g of methane, CH_4, 18.0g of ethane, C_2H_6, and an unknown amount of propane, C_3H_8) were added to t

myrzilka [38]

Explanation:

Part A:

Total pressure of the mixture = P = 5.40 atm

Volume of the container = V = 10.0 L

Temperature of the mixture = T = 23°C = 296.15 K

Total number of moles of gases = n

PV = nRT (ideal gas equation)

$n=\frac{PV}{RT}=\frac{5.40 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.22 mol$

Moles of methane gas = $n_1=\frac{8.00 g}{16 g/mol}=0.5 mol$

Moles of ethane gas = $n_2=\frac{18.0 g}{30 g/mol}=0.6 mol$

Moles of propane gas = $n_3$

$n=n_1+n_2+n_3$

$2.22=0.5 mol +0.6 mol+ n_3$

$n_3= 2.22 mol - 0.5 mol -0.6 mol= 1.12 mol$

Mole fraction of methane = $\chi_1=\frac{n_1}{n_1+n_2+n_3}=\frac{n_1}{n}$

$\chi_1=\frac{0.5 mol}{2.22 mol}=0.2252$

Similarly, mole fraction of ethane and propane :

$\chi_2=\frac{n_2}{n}=\frac{0.6 mol}{2.22 mol}=0.2703$

$\chi_3=\frac{n_3}{n}=\frac{1.12 mol}{2.22 mol}=0.5045$

Partial pressure of each gas can be calculated by the help of Dalton's' law:

$p_i=P\times \chi_1$

Partial pressure of methane gas:

$p_1=P\times \chi_1=5.40 atm\times 0.2252=1.22 atm$

Partial pressure of ethane gas:

$p_2=P\times \chi_2=5.40 atm\times 0.2703=1.46 atm$

Partial pressure of propane gas:

$p_3=P\times \chi_3=5.40 atm\times 0.5045=2.72 atm$

Part B:

Suppose in 100 grams mixture of nitrogen and oxygen gas.

Percentage of nitrogen = 37.8 %

Mass of nitrogen in 100 g mixture = 37.8 g

Mass of oxygen gas = 100 g - 37.8 g = 62.2 g

Moles of nitrogen gas = $n_1=\frac{37.8 g g}{28g/mol}=1.35 mol$

Moles of oxygen gas = $n_2=\frac{62.2 g}{32 g/mol}=1.94 mol$

Mole fraction of nitrogen= $\chi_1=\frac{n_1}{n_1+n_2}$

$\chi_1=\frac{1.35 mol}{1.35 mol+1.94 mol}=0.4103$

Similarly, mole fraction of oxygen

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{1.94 mol}{1.35 mol+1.94 mol}=0.5897$

Partial pressure of each gas can be calculated by the help of Dalton's' law:

$p_i=P\times \chi_1$

The total pressure is 405 mmHg.

P = 405 mmHg

Partial pressure of nitrogen gas:

$p_1=P\times \chi_1=405 mmHg\times 0.4103 =166.17 mmHg$

Partial pressure of oxygen gas:

$p_2=P\times \chi_2=405 mmHg\times 0.5897=238.83 mmHg$

3 0

3 years ago

Carbon-14 is a common isotope of the element. How many electrons

eimsori [14]

I think 8 or 6 im not sure

5 0

3 years ago

Jim went for a 3.75 hour run. How many minutes did he run?

tensa zangetsu [6.8K]

An hour is 60 minutes. So you multiple the hot by 60. You get 180 minutes plus the 75 remaining minutes. The answer is 255

5 0

3 years ago

The volume of a diamond is found to be 2.8 ml. what is the mass of the diamond in carats?

Helen [10]

Answer:

49.14 carat.

Explanation:

From the question given above, we obtained the following data:

Volume of diamond = 2.8 mL

Mass of diamond (in carat) =.?

Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:

Volume of diamond = 2.8 mL

Density of diamond = 3.51 g/mL

Mass of diamond ( in grams) =?

Density = mass /volume

3.51 = mass /2.8

Cross multiply

Mass of diamond (in g) = 3.51 × 2.8

Mass of diamond (in g) = 9.828 g

Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:

1 g = 5 carat

Therefore,

9.828 g = 9.828 g /1 g × 5 carat

9.828 g = 49.14 carat.

Therefore, the mass of the diamond in carat is 49.14 carat.

5 0

3 years ago