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STatiana [176]
3 years ago
7

Which is a step of the scientific method in environmental science

Chemistry
1 answer:
elixir [45]3 years ago
8 0

Answer:

Explanation:

1) make an observation that describes a problem,

2) create a hypothesis,

3) test the hypothesis, and

4) draw conclusions and refine the hypothesis.

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Substance A is a nonpolar liquid and has only dispersion forces amongits constituent particles. Substance B is also a nonpolar l
alekssr [168]

Answer:

(a) when both the liquid are mixed, they become completely miscible as the intermolecular forces between them are equal to the intra molecular forces

(b) since the magnitude of intermolecular force = intra molecular forces, Delta H solution=0

(c) Delta H solute = positive

Delta H solvent = positive

Delta H mix = negative

Explanation:

3 0
3 years ago
Please help :,) I’m being timed
vova2212 [387]

Answer:

B

Explanation:

6 0
3 years ago
What type(s) of intermolecular forces are expected between nocl molecules?
mina [271]
If you draw or search for the molecular geometry of NOCl, you would know that it has a bent shape. This bent shape is a characteristic of a polar molecule. The dominant intermolecular forces for polar compounds is the <em>dipole-dipole force</em>.
4 0
4 years ago
How many moles are present in 454 grams of co2?
babunello [35]
Moles=mass/Mr 
mass=454
Mr=12+16+16=44
So,454/44=10.31mol
Answer is:10.31mol
3 0
3 years ago
Read 2 more answers
A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w
Serhud [2]
Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

A = 50*929,0304

\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

m = 8,5*28,3495

\boxed{m = 240,97075\:g}\Longleftarrow(mass)

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

d =  \dfrac{m}{V} \to V =  \dfrac{m}{d}

V =  \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}

V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

V (volume) = A (Area) * T (Thickness)

89,25\:cm^3 = 46451,52\:cm^2\:*\:T

46451,52\:cm^2*T = 89,25\:cm^3

T =  \dfrac{89,25\:cm^3}{46451,52\:cm^2}

T = 0,001921358009...\:cm

We will convert to millimeters, going through a decimal place on the right

T = 0,01921358009..\:mm

\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark

Hope this helps! :))





8 0
3 years ago
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