Which of the following is a reason to make an armature the parent of a creature

A solution of iron(III) chlorate was poured into a lithium phosphate solution. Would you expect a precipitate to form if 354.0 m

Artist 52 [7]

Answer:

K. Yes, because Qsp > Ksp for iron(III) phosphate

Explanation:

Lithium chlorate is very soluble in water, that means has a big ksp.

Iron (III) phosphate has a ksp of 1.3x10⁻²²

Ksp formula of iron (III) phospate is:

FePO₄(s) ⇄ Fe³⁺(aq) + PO³⁻(aq)

Ksp = [Fe³⁺] [PO₄³⁻] = 1.3x10⁻²²

Molar concentration of Fe³⁺ and PO₄³⁻ is:

[Fe³⁺] = 0.340L ₓ (2.52x10⁻⁹mol / L) ÷ (0.354L + 0.520L) = 9.8x10⁻¹⁰M

[PO₄³⁻] = 0.520L ₓ (4.65x10⁻¹¹mol / L) ÷ (0.354L + 0.520L) = 2.78x10⁻¹¹M

Replacing in Ksp formula:

Qsp = [9.8x10⁻¹⁰] [2.78x10⁻¹¹M] = 2.72x10⁻²⁰

As Qsp > Kps, the equlibrium will shift to the right decreasing the ions concentrations producing FePO₄(s), a precipitate

The ions decreases its concentration until Q = Kps

Thus, right answer is:

K. Yes, because Qsp > Ksp for iron(III) phosphate

6 0

3 years ago

Laura is supplied with 5 bolts (B) and 12 nuts (N). She attached the nuts to the bolts in a 2:1 ratio (N2B). Which of the reacta

Andrews [41]

Answer:

The bolts will run out first, so these will limit how much product can be formed.

(option C is correct)

Explanation:

Step 1: Data given

Number of bolts = 5

Number of nuts = 12

ratio N:B = 2:1

Step 2

Since the ratio N:B is 2:1 we have 2 nuts for each bolt

When we have 2 bolts we have 4 nuts

When we have 3 bolts we have 6 nuts

When we have 4 bolts we have 8 nuts

When we have 5 bolts we have 10 nuts

We don't have more bolts, but there are still 2 nuts left. This means the bolts will run out first, so these will limit how much product can be formed.

(option C is correct)

5 0

3 years ago

At equilibrium, a 1.00 M OClÈ solution has an [OHÈ] of 5.75 × 10ÈÊ M. Which of the following is the correct pH of the solution?

omeli [17]

pOH = 9.2

pH = 4.8
That's your answer!!

Hope I helped!! :)

3 0

3 years ago

What pressure (in kilopascals) is exerted by 4.20 moles of Xenon gas in a 15.0 L container at 280.0 K?

aniked [119]

Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa

Explanation:

The question requires us to calculate the pressure, in kPa, connsidering the following information:

number of moles = n = 4.20mol

volume of gas = V = 15.0L

temperature of gas = T = 280.0 K

We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:

$PV=nRT\rightarrow P=\frac{nRT}{V}$

Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:

R = 8314.46 L.Pa/K.mol

Applying the values given by the question to the rearranged equation above, we'll have:

$\begin{gathered} P=\frac{nRT}{V} \\ \\ P=\frac{(4.20mol)\times(8314.46L.Pa/K.mol)\times(280.0K)}{(15.0L)}=652\times10^3Pa \end{gathered}$

Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.

8 0

1 year ago

Can you guys please help me I will mark brainliest to whoever answers this right.

Sphinxa [80]

Wants: a stove top- you don’t need it to make food but it’s more convenient.
Wants: automobile- you don’t need a car but it’s easy to go places and faster. You could use a bike instead however it’s not as convenient to some of us.

Needs: sun- we need the sun to stay warm and live and to keep earth living.
Needs:our heat- we need the heat our body provides to live and function

7 0

3 years ago