Which of the following is a reason to make an armature the parent of a creature

Concentrated sulfuric acid (18.3 M) has a density of 1.84 g/mL.

lianna [129]

The number of mole sulphuric acid in each mL of solution is 0.0183 mol/mL.

<h3>What is concentration?</h3>

Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.
Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
There are different types of molar (quantity) concentration, including normal concentration and osmotic concentration.

<h3>How is concentration determined?</h3>

Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.
To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.

Learn more about concentration here:

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6 0

2 years ago

How many joules of heat is lost when a 64 g piece of copper cools from 375 oC to 26 oC? The specific heat of copper is 0.38 J/go

Svetlanka [38]

Answer: 8500 J lost or -8500 J

Explanation:

q=cmt

t=375-26

t=349

q=0.38(64)(349)

q=8487.68 J

Answer must have 2 sig figs, which means it rounds to 8500 J.

7 0

4 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$