Answer:
the solution is x = 2 and y = 4 OR (2,4)
Step-by-step explanation:
From the question
Equation 1: 3x-2y= -2
Equation 2: 3x + y = 10
Subtract equation 1 from equation 2, that is
3x + y = 10 - (3x -2y = -2)
You get
3x - 3x + y - (-2y) = 10 - (-2)
0 + y + 2y = 10 + 2
3y = 12
Divide both sides by 3
∴ y = 12/3
y = 4
Substitute the value of y into equation 2 to get x
3x + y = 10
3x + 4 = 10
Then,
3x = 10 - 4
3x = 6
Divide both sides by 3
∴ x = 6/3
x = 2
Hence, the solution is x = 2 and y = 4
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The ways we can prove the triangles congruent:
SAS (side, angle, side)
ASA (angle, side, angle)
AAS (angle, angle, side)
SSS (all sides equal)
RHS/HL (Right Angle-Hypotenuse-Side/Hypotenuse-legs)
In these cases:
A. <B = <E
<A = <D
AC=DF
AAS (angle, angle, side) could be used.
B. AB=ED
BC=EF
AC=DF
SSS (all sides equal) could be used.
C.<BEA=<CED (right opposite angles)
As there is only one pair of equal angles we can find,there is not enough information.
D.<B = <E
BC=CE
<ECD < ACE(right opposite angles)
ASA (angle, side, angle) could be used.
Hope it helps!
Answer:
63
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Step-by-step explanation:
