Answer:
Cl^- <S^2-<Sc^3+ <Ca^2+<K^+
Explanation:
We know that ionic radius of ions decreases from right to left in the periodic table. This is because, ionic radii decreases with increase in nuclear charge. This explains why; Sc^3+ <Ca^2+<K^+.
Secondly, even though Cl^- is isoelectronic with S^2-, the size of the nuclear charge in Cl^- is larger compared to that of S^2- . Hence Cl^- is smaller than S^2- in ionic radius owing to increased nuclear attraction in Cl^-.
The answer to this question would be that the amount of No and SO3 would increase. The correct choice is C.
Answer:
It is true. a) 0.25 mol
Explanation:
<em>Hello </em><em>there?</em>
To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.
The chemical equation is;
3Mg(s) + N2(g) => Mg3N2(s)
1 mole of Mg = 24g
We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)
From our equation,
Mole ratio = 3 : 1, (Mg : N2)
1 mol Mg = 24g
x mol Mg = 18g
x mol Mg = (18/24) = 0.75 mol Mg
But mole ratio = 3 : 1 (Mg : N2)
This means that 3 => 0.75 mol Mg
What about ratio 1 of N2?
N2 = (0.75 mol ÷ 3)/1
= 0.25 mol N2
<em>I </em><em>hope</em><em> </em><em>this </em><em>helps</em><em> </em><em>you </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Ha</em><em>v</em><em>e </em><em>a </em><em>nice </em><em>studies.</em><em> </em><em />
Answer:
Kc = 3.72 × 10⁶
Explanation:
Let's consider the following reaction:
NH₄HS(g) ⇄ NH₃(g) + H₂S(g)
At equilibrium, we have the following concentrations:
[NH₄HS] = 0.196 M (assuming a 1 L flask)
[NH₃] = 9.56 × 10² M
[H₂S] = 7.62 × 10² M
We can replace this data in the Kc expression.
![Kc=\frac{[NH_{3}] \times [H_{2}S] }{[NH_{4}HS]} =\frac{9.56 \times 10^{2} \times 7.62 \times 10^{2}}{0.196} =3.72 \times 10^{6}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNH_%7B3%7D%5D%20%5Ctimes%20%5BH_%7B2%7DS%5D%20%7D%7B%5BNH_%7B4%7DHS%5D%7D%20%3D%5Cfrac%7B9.56%20%5Ctimes%2010%5E%7B2%7D%20%20%5Ctimes%207.62%20%20%5Ctimes%2010%5E%7B2%7D%7D%7B0.196%7D%20%3D3.72%20%5Ctimes%2010%5E%7B6%7D)
