In order to do this, we have to first know the significant figure rules.
<span>Rule #1: All non-zero digits are significant. (1234)
Rule #2: Zeros in front of a number are not significant. (0.093)
Rule #3: Zeros between non-zero digits are significant. (78309)
Rule #4: Zeros at the end of a number are significant if there is a decimal point in the number. (0.05470)
So by going by the rules, 56.0g has three sig figs, because there is a decimal point.
0.0004m only has one sig fig, according to Rule #2.
1003ml has 4 sig figs, because the zeroes are wedged in the two sig fig numbers.
And lastly, 0.0350s has 3 sig figs because the number after a decimal point counts.
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After oil is naturally refined underground, the only way that a viable deposit of hydrocarbon can form is if the oil encounters some kind of trap.
Answer:
Gold
Explanation:
We are given that
Mass of sample ,m=385 g
Volume ,V=20mL
We have to find the coin is gold or yellow brass.
We know that
Density=
Using the formula
Density of coin=19.3g/mL
Density of gold=19.3g/mL
Hence, the coin is gold.
Answer:
Pure elements:
Hydrogen(H)
Nitrogen(N)
Magnesium (Mg)
Pure Compounds:
Oxygen gas(O2)
Water (H2O)
Ammonia (NH3)
Explanation:
Hope it helps.Please mark me brainliest.^-^
Answer:
Here's what I get
Explanation:
CH₃CH₂CH₂CH₂CH₂CH₃ — hexane
CH₂=CHCH₂CH₂CH₂CH₃ — hex-1-ene is the preferred IUPAC name (PIN). 1-Hexene is accepted
CH₃C≡CCH₃ — but-2-yne (PIN); 2-butyne is accepted
CH₃CH(CH₃)CH₂CH₂CH₃ — 2-methylpentane
CH₃CH₂CHCICH₂CH₃ — 3-chloropentane
