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den301095 [7]
3 years ago
15

How much power does a 2000 kg car need to accelerate from 20 m/s to 35 m/s in 7 seconds?

Physics
1 answer:
Alexus [3.1K]3 years ago
3 0

firstly you get your acceleration with the formula, a=v-u/t. Then you use the formula for kinetic energy 1/2mv^2

then you can finally get the answer for power by dividing your previous answer by the time

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What is the difference between a series circuit and a parallel circuit?
Angelina_Jolie [31]
Parallel has more than one circuit or form of energy

series has only one form of energy circuit
6 0
3 years ago
A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

\mu = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

\omega = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0
3 years ago
Light incident upon a pane of glass slows down in passing through the glass, Does it emerge at a slower speed or at its initial
Simora [160]

Answer:

It will emerge at its initial speed not a slower speed.

Explanation:

It will emerge at the initial speed because the medium at the point of emergence is the same as the medium before incidence.

Light moves at a constant speed in any particular medium. Hence, the speed of light in air is constant in air and the speed of light in glass is constant in glass.

4 0
2 years ago
8. What is the momentum of a 120-kg professional fullback running<br> across the line at 11.2 m/s?
Alchen [17]

Answer:

134r kgm^-1 or 1344 kg /m

Explanation:

Momentum is is given by:

p=mv

Where:

p is momentum, m is mass in kg and v is velocity in ms−1

p=120kg×11.2 m/ s= 1344 kgms=1344kgm^−1

5 0
2 years ago
radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the
Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

v = 3 \times 10^8 m/s

the altitude of the airplane is given as

h = 1 \times 10^4 m

now we know that time taken by the signal to reach the control tower is given as

t = \frac{d}{v}

now it is given as

t = \frac{1 \times 10^4 }{3 \times 10^8}

t = 3.33 \times 10^{-5} s

so above is the time taken by the signal to reach the control tower

3 0
3 years ago
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