Answer:

Explanation:
We should first find the velocity and acceleration functions. The velocity function is the derivative of the position function with respect to time, and the acceleration function is the derivative of the velocity function with respect to time.

Similarly,

Now, the angle between velocity and acceleration vectors can be found.
The angle between any two vectors can be found by scalar product of them:

So,

At time t = 0, this equation becomes

Answer:
1) a radio are uses by astronomy
2) 6 bilion waves
3) expert vertified
Explanation:
1) in contrast to an "ordinary" telescope, which receives visible light, a radio telescope "sees" radio waves emitted by radio sources, typically by means of a large parabolic ("dish") antenna, or arrays of them.and Radio telescopes are also the primary means to track space probes, and are used in the SETI project. so must been
radio are almostly
ceiver by astronomy
2) Radio waves have the longest wavelengths in the electromagnetic spectrum.
3)Expert Verified
Radio telescopes are telescopes that are specially designed for observation of long light wavelengths
CARRY ON ✨
Answer:
Explanation:
Caty , Use the relativity formula for length. ( they teach this in H.S. ? ) it's from my Modern Physics in college, A 300 level class
L = 

L = 3 
L = 0.9367496998 meters
L = 0.94 meters approx