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Olin [163]
3 years ago
12

What is the slope of (3,5) and (-2,1)

Mathematics
2 answers:
patriot [66]3 years ago
7 0

the slope of (3,5) and (-2,1) would be -4/-5

calculating the slope:

(y_{2} - y_{1}) ÷ (x_{2} - x_{1})

1 - 5 = -4

-2 - 3 = -5

fgiga [73]3 years ago
4 0

Answer:

m = 4/5

Step-by-step explanation:

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6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

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Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

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now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
3 0
3 years ago
What is the missing side and what is the answer rounded to the nearest tenth?
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The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3.  Thus, the perpendicular line has the slope -1/3.

Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:

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-18 = -8 + 3b.  Thus, -10 = 3b, and so b must be -10/3.

The desired equation is    

y = (-1/3)x - 10/3, or

y = (-1/3)(x + 10)

8 0
3 years ago
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