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KATRIN_1 [288]
3 years ago
15

Evalute b (caret) 2-5c b=15 and c =9

Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer: look at the 4 picture for the answer’s

Question: 2-5c b=15

Question: 2-5c c=9

Step-by-step explanation: hope this help:)

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PLZ HELP ME OVER HERE!!
riadik2000 [5.3K]

Answer:

x = 5

Step-by-step explanation:

If x + 5 = 10, then x would have to be 5 because 5 + 5 = 10.

The way you would solve this would be:

x + 5 = 10

subtract 5 from both sides of the equation

x + 5 - 5 = 10 - 5

simplify:

x = 5

5 0
3 years ago
Two friends start a business. Together they spent 800 dollars for their initial inventory. They will sell all of their initial i
Paul [167]
Their selling price was 2.45 times the price they bought it. If they split the profit evenly and there was two of them, multiply their profit by two and divide that number by 800 to find how much more they sold it for, so they sold it for 245% more than they bought it
5 0
4 years ago
Elisa needs 40 shirts for a charity. One store is selling shirts for $6.95 each. Another store says that the total for al 40 shi
xxTIMURxx [149]
Well, let us figure out what the first store will cost.
40*6.95=278
Now for the second store
325*0.8=260

So the first store is $278, while the second store is $260, so Elisa should buy shirts from the second store
7 0
3 years ago
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
4 years ago
Use the net as an aid to compute the surface area of the triangular prism.
Ray Of Light [21]

Answer:

790

Step-by-step explanation:

i just took the test

3 0
3 years ago
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