The answer would be -161z-3a
Answer:
Step-by-step explanation:
Set B = 60 elements
Set A = x elements
A∩B = 12
A∪B = 82
x = (82+12 - 60) = 34 elements
Answer:
u[jkhpoi 9yuij ijiuyko yu yuoj kyujokyj[io jy jh[oyujokhk tkouykoj tykkkjio nn uihjbnj kmvbhio mjghkobvjkoihjm nkligfj
Step-by-step explanation:
The term circular mil is common in expressing the cross sectional area of a wire. Electrical wires have very minute diameters that are often measured a thousandth of an inch. Hence, when you find the area of the circular wire, for convenience, the unit used is circular mil which is equivalent to one-thousandth of an inch.
For example, a wire has a diameter of 6×10⁻⁵ inches. To find its area:
A = πr² = π( 6×10⁻⁵ /2)² = 2.83×10⁻⁹ in²
Since 1 mil = 1/1000 (inch) or 0.001 inch
A = (2.83×10⁻⁹ in²)* (1 mil/ 0.001 inch)²
A = 0.00283 circular mils
Answer:
Difference in volume between the two vinyl records = 3.872 in³
Step-by-step explanation:
Complete Question
2columbia records unveiled the lp (a vinyl record) in the waldorf astoria on june 18, 1948, in two formats: 10 inches in diameter, matching that of 78 rpm singles, and 12 inches in diameter. if the thickness of one vinyl record is 0.112 in, then determine the difference in volumes between the 10 inch and 12 inch records.
Each of the vinyl records will be modelled as a cylinder
Volume of a cylinder = πr²h
For the 12 inches diameter records.
r = (12/2) = 6 inches
h = thickness = 0.112 inches
Volume = π × (6²) × 0.112 = 12.672 in³
For the 10 inches diameter records
r = (10/2) = 5 inches
h = thickness = 0.112 inches
Volume = π × (5²) × 0.112 = 8.8 in³
Difference in volume between the two vinyl records = 12.672 - 8.8 = 3.872 in³
Hope this Helps!!!
