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Nadusha1986 [10]
3 years ago
8

A manager is considering three new machines for filling boxes of cereal at a processing plant. Each of the three machines is ass

igned to 10 randomly selected employees. The time required to fill 25 boxes using the machine is recorded. How many treatments does this single-factor experiment have
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

3

Step-by-step explanation:

Given that :

Number of machines which are asre assigned 10 different randomly selected employees = 3

Hence, the number of treatments in the single - factor experiment is 3. This is because from the knowledge of ANOVA(Analysis of Variance), the letter 'k' is used to depict the number of treatment which is equivalent to the number of independent groups which we want to experiment or compare. Since each of the 3 new machines are treated independently. Hence, we have 3 treatments.

Also the number of groups k which are assigned the same Number of sample sizes in the comparison group is the Number of treatments on the analysis.

Hence, 3 different groups are each assigned 10 random employees. Then the number of treatments equals 3.

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According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers
postnew [5]

Answer:

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Step-by-step explanation:

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S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

                        P(S/L) = \frac{P(S\bigcap L)}{P(L)}  

                        P(S\bigcap L) = P(S/L) * P(L)

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So,  P(S\bigcap L) = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

      P(L/S) = \frac{P(S\bigcap L)}{P(S)}

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

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Hence, probability that a smoker has lung disease is 0.2132 .

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3 years ago
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