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Romashka [77]
3 years ago
13

The number 0 is a critical point of the autonomous differential equation dx/dt = 7xn, where n is a positive integer. For what va

lues of n is 0 asymptotically stable? Semi-stable? Unstable?
Mathematics
1 answer:
Lena [83]3 years ago
4 0

Answer:

a) 0 is stable when n = odd

b) 0 is semi-stable when n = even

c) 0 is unstable when n is odd

Step-by-step explanation:

Th differential equation for this question

dx/dt = x^n

n = positive integer

<u>a) value of n where 0 is stable </u>

0 is stable when x^n is replaced with -x^n

because considering n to be an odd number

-x^n > 0 when x < 0    while -x^n < 0 when x > 0

∴ In this scenerio we can conclude that 0 is stable when  n = odd number

<u>b) Value of n where 0 is Semi-stable </u>

assuming n is an even number

x^n > 0  for all the values of x

<u>c) Value of n where 0 is unstable </u>

lets assume n is odd

when n < 0,  xⁿ < 0

when n > 0,  xⁿ > 0

i.e. 0 is asymptotically unstable when n is an odd number

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