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Bingel [31]
3 years ago
14

A light bulb contains 0.0560 g of argon gas with a pressure of 1.34 atm at 26.0 c. The light bulb is then turned on and, after a

period of time, the temperature rises to 179c. Calculate the final pressure the light bulb
Chemistry
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

Final pressure of light bulb is 2.03 atm.

Explanation:

Given data:

Initial pressure = 1.34 atm

initial temperature = 26 °C

Finial temperature = 179 °C

Final pressure = ?

Formula:

P1/T1 = P2/T2

Solution:

First of all we will convert the °C into kelvin.

179 +273 = 452 K

26 +273 = 299 K

P2 = P1×T2/T1

P2 = 1.34 atm . 452 K / 299 K

P2 = 605.68 atm/ 299

P2 = 2.03 atm

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An Insulator.

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Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
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Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

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According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

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5 0
2 years ago
7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken
Nana76 [90]

<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution.  The equation used to calculate molarity of the solution is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M

Hence, the molarity of Iron (III) chloride is 0.622 M.

3 0
2 years ago
A sample of methane occupies a volume of 174.0 mL at 25 C and exerts a pressure of 1030.0 mmHg if the volume of the gas is allow
PolarNik [594]

Answer:

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P2= (1,39 atm x 0,174L)/0,650L= 0,37 atm

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Explanation:

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