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Nitella [24]
3 years ago
8

What are the relationships between temperature and viscosity of water?

Chemistry
1 answer:
iris [78.8K]3 years ago
8 0

Explanation:

Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.

temperature?

The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.

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Calculate the equilibrium constant for the reaction: 2 Cr + 3 Pb2+ ----> 3 Pb + 2 Cr3+ at 25oC. Eocell = 0.61 V
sattari [20]

Answer:

The value is  K  =  8*10^{61}

Explanation:

From the question we are told that

    The equation is  2 Cr  +  3Pb^{2+} \to 3Pb + 2Cr^{3+}

     The  temperature is  T = 25^oC =  298 K   [room  \ temperature ]

     The  emf at standard condition is  E^o_{cell}  =  0.61 \  V

Generally at the cathode

      3Pb^{2+}(aq) + 6 e- --> 3Pb(s)

  At the anode

      2Cr^{3+} + 6e^- \to  2Cr

Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  

       G =  n*  F *  E^o_{cell}

Here  n  is  the no of electron  with value n = 6

       F  is  the Faraday's constant with value 96487 J/V

  =>   G =  6  * 96487 *  0.61

  =>   G = 3.5 *10^{5} \  J

This Gibbs free energy can also be represented mathematically as

       G =  RTlogK

Here  R  is the cell constant with value 8.314J/K

           K is the equilibrium constant

From above

=>  K  =  antilog^{\frac{G}{ RT} }

Generally  antilog =  2.718

=>K  =  2.718^{\frac{3.5 *10^5}{ 8.314* 298} }

=>   K  =  8*10^{61}

       

         

       

         

6 0
3 years ago
What is the maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3
kvv77 [185]

Answer:

6.79 g of phosphine can be produced

Explanation:

The reaction is this:

3H₂ + 2P → 2PH₃

We have the mass of the two reactants, so let's find out the limiting reactant, so we can work with the equation. Firstly, we convert the mass to moles (mass / molar mass)

6.2 g / 30.97 g/mol = 0.200 moles of P

4g / 2 g/mol = 2 moles of H₂

Ratio is 3:2.

3 moles of hydrogen react with 2 moles of P

Then, 2 moles of H₂ would react with (2 . 2)/ 3 = 1.3 moles of P.

We have only 0.2 moles of P, so clearly the phosphorous is the limiting reactant.

Ratio is 2:2. So 2 moles of P can produce 2 moles of phosphine. Therefore, 0.2 moles of P must produce the same amount of phosphine.

Let's convert the moles to mass ( mol . molar mass)

0.2 mol . 33.97 g/mol = 6.79 g

3 0
3 years ago
Enter the electron configuration for the ion most likely formed by phosphorus. Express your answer in the order of orbital filli
Bingel [31]

Answer:

[Ne] 2s2 2p3

Explanation:

Phosphorus will most likely have an ion that will be 3- because it wants to have a full outer shell. Thus, the elctron configuration is: 1s2 2s2 2p6 3s2 3p3.

4 0
3 years ago
What is the value of the equilibrium constant for this redox reaction?
aivan3 [116]
Correct  answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
We know that, 
Ecell = \frac{0.0592}{n}log(K),
where n = number of electrons = 2 (in present case)
K = equilibrium constant.

Also, Ecell = <span>+1.56 v

Therefore, 1.56 = </span>\frac{0.0592}{2}log(K)
Therefore, log (K) = 52.703
Therefore,  K = 5.04 X 10^52


8 0
3 years ago
Read 2 more answers
Would an atom of sodium and an atom of potassium join to form an ionic compound?
Sever21 [200]
No they wouldn't. <span>You can't make an </span>ionic compound<span> with these elements.</span>
7 0
3 years ago
Read 2 more answers
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